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 应用科技  2018, Vol. 45 Issue (5): 44-50, 43  DOI: 10.11991/yykj.201701010 0

### 引用本文

FENG Chi, MA Xiumin, GAO Shan, et al. Realization of photoelectric constant temperature system with refrigeration[J]. Applied Science and Technology, 2018, 45(5), 44-50, 43. DOI: 10.11991/yykj.201701010.

### 文章历史

1. 哈尔滨工程大学 信息与通信工程学院，黑龙江 哈尔滨 150001;
2. 西安航空发动机(集团)有限公司，陕西 西安 710021

Realization of photoelectric constant temperature system with refrigeration
FENG Chi1, MA Xiumin1, GAO Shan1, WANG Zhaofeng2
1. College of Information and Communication Engineering, Harbin Engineering University, Harbin 150001, China;
2. Xi’an Aero-engine (Group) Ltd., Xi’an 710021, China
Abstract: In order to improve the performance of the near-infrared temperature measuring system, this paper proposes a constant temperature control system in the near-infrared temperature measuring instrument to ensure that the photodetector in the near-infrared temperature measuring instrument can work under the same temperature every time for improving the stability and resolution of this system. The constant temperature system uses thermoelectric cooler (TEC) as the cooling device and ADN8830 as the key controller. The peripheral circuit of ADN8830 was optimized in the design, and The PID compensation network of the system was simulated in Simulink and then debugged actually. Finally, by measuring the value of the current through the TEC and using the chart it can be known that this constant temperature system can reach the set temperature quickly and accurately within 10s and keep the set temperature unchanged for a long time.
Keywords: thermoelectric cooler    ADN8830    stable boundary method    simulation of PID    Simulink    constant temperature    photodetector    refrigeration

1 半导体制冷器

2.1 温度设定

2.2 选频网络

 ${f_{{\rm{SWITCH}}}} = \frac{{150 \times {{10}^9}}}{{{R_{{\rm{FREQ}}}}}}$

 ${R_{{\rm{FREQ}}}} = 150 \; {\rm{k}}\Omega$
3 PID补偿网络仿真与实现

1）将积分和微分系数设置为0，选择比例系数较小的，并将系统按照此系数运行。

2）求取临界振荡周期和临界增益。

3）按照表4的经验公式和校正装置类型整定相应的PID参数。

3.2 仿真结果

3.3 仿真结果与实际参数换算

 ${K_{\rm{P}}} = {R_1}/{R_3}$

 ${K_{\rm{I}}} = 1/{R_3}{C_1}$

 ${K_{\rm{D}}} = {R_1}{C_2}$

4 实验结果

5 结论