郑州大学学报(理学版)  2017, Vol. 49 Issue (2): 30-36  DOI: 10.13705/j.issn.1671-6841.2016208

引用本文  

杨彩虹, 胡志兴. 一类具有饱和发生率和治愈率的SEIR模型研究[J]. 郑州大学学报(理学版), 2017, 49(2): 30-36.
YANG Caihong, HU Zhixing. Analysis of an SEIR Model with Saturated Incident Rate and Treatment Rate[J]. Journal of Zhengzhou University(Natural Science Edition), 2017, 49(2): 30-36.

基金项目

国家自然科学基金项目(61174209, 11471034)

通信作者

胡志兴(1962—),男,陕西汉中人,教授,主要从事非线性动力系统与混沌、生物数学等方面的研究, E-mail: huzhixing@ustb.edu.cn

作者简介

杨彩虹(1991—), 女, 山东滨州人, 硕士研究生, 主要从事生物数学的研究, E-mail:13356280704@189.cn

文章历史

收稿日期:2016-08-23
一类具有饱和发生率和治愈率的SEIR模型研究
杨彩虹 , 胡志兴     
北京科技大学 数理学院 北京 100083
摘要:研究了一类具有饱和发生率和治愈率的SEIR传染病模型, 并且考虑了垂直传染与免疫接种等因素的影响.首先分析平衡点的存在性,并通过计算得到基本再生数R0.通过研究发现,系统在R0=1处出现了后向分支,并得到控制疾病的一个新的阈值R0*,即当R0 < R0* < 1时传染病会逐渐消失.然后讨论平衡点的局部稳定情况及出现后向分支的充分条件.最后分析平衡点的全局稳定性.
关键词饱和发生率    饱和治愈率    垂直传染    预防接种    SEIR    后向分支    
Analysis of an SEIR Model with Saturated Incident Rate and Treatment Rate
YANG Caihong , HU Zhixing     
School of Mathematics and Physics, University of Science & Technology Beijing, Beijing 100083, China
Abstract: An SEIR epidemic model with saturated incident rate and saturated treatment function and considered the impact of vaccination and vertical transmission was studied. The existence of equilibrium point of the model was studied and the basic reproductive number R0 of the model was given. It was shown that there existed a backward when R0=1. At this time a new threshold R0* was obtained and got a conclusion that the disease would gradually become extinct when R0 < R0* < 1. Then, the locally stability of equilibrium point of the model was studied and the sufficient condition of the model appear backward was given. Finally, the globally stability was discussed.
Key words: saturated incidence rate    saturated treatment    vertical transmission    vaccination    SEIR    backward branch    
0 引言

目前为止已经建立的传染病模型有SI, SIS, SIR, SIRS, SEIR, SEIRS, SVIR等.其中SEIR模型与SIR模型的区别在于SEIR模型对人口的分类上出现了潜伏者E.文献[1-4]分别对SIR, SVIR, SEIR模型进行了研究,并且考虑了不同的治愈函数、垂直传染、预防接种等因素的影响.本文研究了一类新的具有饱和发生率与饱和治愈率的SEIR传染病模型.

1 模型建立

考虑到接触传播、垂直传播、预防接种等因素的影响,建立模型(1),

$ \left\{ \begin{array}{*{35}{l}} \frac{{\rm{d}}S}{{\rm{d}}t}=bm\left( S+E+R \right)+p\delta I-\frac{\beta SI}{1+\alpha I}-bS, \\ \frac{{\rm{d}}E}{{\rm{d}}t}=\frac{\beta SI}{1+\alpha I}-bE-\omega E-\varepsilon E, \\ \frac{{\rm{d}}I}{{\rm{d}}t}=\omega E+q\delta I-\delta I-\gamma I-\frac{\xi I}{1+kI}, \\ \frac{{\rm{d}}R}{{\rm{d}}t}\mathit{=\gamma }I+\frac{\xi I}{1+kI}+b{m}'\left( S+E+R \right)+\varepsilon E-bR, \\ \end{array} \right. $ (1)

其中:S, E, I, R分别表示易感者、潜伏者、染病者和恢复者,人口总数记为NN=S+E+I+R,为了方便研究,假设N=1;bS, E, R的自然出生率和自然死亡率;δI的出生率与死亡率;m′为易感者、潜伏者、恢复者的新生儿的预防接种比例(m+m′=1);q为垂直感染率(p+q=1);ω为潜伏者转变成患病者的概率;ε为潜伏者的自然恢复率;γ为患病者的自然恢复率;$ \frac{{\beta SI}}{{1 + \alpha I}} $为饱和发生率, $ \frac{{\xi I}}{{1 + kI}} $为饱和治愈率(k>0).

化简得

$ \left\{ \begin{array}{l} \frac{{{{\rm{d}}}\mathit{S}}}{{{{\rm{d}}}t}} = bm\left( {1 - I} \right) + p\delta I - \frac{{\mathit{\beta SI}}}{{1 + \alpha I}} - bS,\\ \frac{{{{\rm{d}}}\mathit{E}}}{{{{\rm{d}}}t}} = \frac{{\mathit{\beta SI}}}{{1 + \alpha I}} - \left( {b + \omega + \varepsilon } \right)\mathit{E},\\ \frac{{{{\rm{d}}}\mathit{I}}}{{{{\rm{d}}}t}} = \omega E - p\delta I - \delta I - \gamma I - \frac{{\xi I}}{{1 + kI}}. \end{array} \right. $ (2)

$ \frac{{{{{\rm{d}}}}\left( {S + E + I} \right)}}{{{{{\rm{d}}}}t}} = bm-bmI-bS-bE - \varepsilon E - \gamma I - \frac{{\xi I}}{{1 + kI}} $,得到Ω={(S, E, I)∈R+3|0≤S+Em, 0≤I≤1}.

2 平衡点存在性分析

系统(2) 有无病平衡点P0=(m, 0, 0),且基本再生数为$ {R_0} = \frac{{\beta \omega m}}{{(b + \omega + \varepsilon )(p\delta + \gamma + \xi )}} $.由式(2) 可得

$ \mathit{S} = \frac{{\left( {\left( {p\delta + \gamma } \right)\left( {1 + kI} \right) + \xi } \right)\left( {1 + \alpha I} \right)\left( {b + \omega + \varepsilon } \right)}}{{\mathit{\beta }\omega \left( {1 + kI} \right)}};\mathit{E = }\frac{{\left( {p\delta + \gamma } \right)I}}{\omega }{\rm{ + }}\frac{{\xi I}}{{\left( {1{\rm{ + }}kI} \right)\omega }}, $ (3)

将式(3) 代入系统(2) 的第一个等式得

$ A{I^2}{\rm{ + }}BI{\rm{ + }}C{\rm{ = }}0, $ (4)

其中:$ B = \omega \beta (bm\left( {1-k} \right)-p\delta ) + (b + \omega + \varepsilon )(\alpha b + \beta )(p\delta + \gamma + \xi ) + kb(b + \omega + \varepsilon )(p\delta + \gamma ) $$A = k[\omega \beta (bm-p\delta ) + (b + \omega + \varepsilon )(p\delta + \gamma )(\beta + \alpha b)] > 0 $$ C = b(b + \omega + \varepsilon )(p\delta + \gamma + \xi )(1-{R_0}) $.

显然R0=1时,C=0;R0>1时C < 0;R0 < 1时C>0.由此可知系统(2) 可能存在两个正根${I_1} = \frac{{-B-\sqrt \Delta }}{{2A}} $$ {I_2} = \frac{{-B-\sqrt \Delta }}{{2A}} $,其中Δ=B2-4AC.当Δ>0时方程(4) 有两个根,若R0>1,则I1 < 0,I2>0;若B≥0,R0 < 1,则I1 < 0,I2 < 0;若B < 0,R0 < 1,则I1>0,I2>0.当Δ < 0时,方程(4) 无解.将C=b(b+ω+ε)(+γ+ξ)(1-R0)代入Δ < 0,得B2-4Ab(b+ω+ε)(+γ+ξ)(1-R0) < 0,从而推出

$ {R_0} < 1 - \frac{{{B^2}}}{{4Ab\left( {b + \omega + \varepsilon } \right)\left( {p\delta + \gamma + \xi } \right)\left( {1 - {R_0}} \right)}} \buildrel \Delta \over = R_0^*. $

由上面的分析可以得定理1.

定理1 1) 当R0>1时, 系统(2) 有一个地方病平衡点P2=(S2, E2, I2).

2) 当R0=1, 若B < 0时,系统(2) 有一个地方病平衡点P2=(S2, E2, I2),其中$ {I'_2} = \frac{B}{A} $.

3) 当R0 < 1, 若B≥0时,系统(2) 没有地方病平衡点.

4) 当B < 0, 若R0 < R0* < 1时,系统(2) 没有地方病平衡点; 若B < 0, R0*R0 < 1时,系统(2) 有两个地方病平衡点P1, P2, 其中R0=R0*P1=P2.

3 局部稳定性与后向分支 3.1 无病平衡点P0处的局部稳定性

定理2 当R0 < 1时, 无病平衡点P0是局部渐近稳定的,当R0>1时,无病平衡点P0是不稳定的.

证明 系统(2) 在无病平衡点P0处的雅可比矩阵为

$ \mathit{\boldsymbol{M}}\left( {{E_0}} \right) = \left[ {\begin{array}{*{20}{c}} { - b}&0&{ - bm - \mathit{\beta m + p}\delta }\\ 0&{ - \left( {b + \omega + \varepsilon } \right)}&{\mathit{\beta m}}\\ 0&\omega &{ - \left( {p\delta + \gamma + \xi } \right)} \end{array}} \right], $

特征方程为(λ+b)(λ2+(b+ω+ε++γ+ξ)λ+(b+ω+ε)(+γ+ξ)-βωm)=0,显然λ0=-bλ1λ2λ2+(b+ω+ε++γ+ξ)λ+(b+ω+ε)(+γ+ξ)-βωm=0的解, 且λ1+λ2=-(b+ω+ε++γ+ξ),λ1·λ2=(b+ω+ε)(+γ+ξ)-βωm,由此可得,当R0 < 1时,λ1λ2都为负,所以无病平衡点P0是局部渐近稳定的;当R0>1时,λ1λ2异号, 所以P0是不稳定的.由定理1可知,当B < 0时,R0=1是分支界限,且由定理2知,无病平衡点的稳定性在此发生变化.

3.2 后向分支

定理3 当B < 0时,系统(2) 在R0=1处出现后向分支(见图 1).

图 1 系统在R0=1处出现后向分支 Figure 1 The backward bifurcation diagram when R0=1

为了进一步得到后向分支出现的条件,考虑以φ为参数的一般系统

$ \frac{{{{\rm{d}}}\mathit{x}}}{{{{\rm{d}}}\mathit{t}}} = f\left( {x,\varphi } \right),f:{{\mathbf{R}}^n} \times {\mathbf{R}} \to {{\mathbf{R}}^n},f \in {C^2}\left( {{{\mathbf{R}}^n} \times {\mathbf{R}}} \right). $ (5)

假设对于任意φ,点0都是系统(5) 的平衡点, 特别地,对φ=0,f(0, φ)≡0.

由文献[5]中定理4.1可知,当φ=0时出现跨临界分岔, 即当a1 < 0且a2>0时,在φ=0处会出现前向分支;当a1>0且a2>0时,在φ=0处会出现后向分支.令ξ为系统(2) 的分支参数, 令S=x1, E=x2, I=x3,则系统(2) 变成

$ \left\{ \begin{array}{l} \frac{{{{\rm{d}}}{\mathit{x}_1}\left( t \right)}}{{{{\rm{d}}}\mathit{t}}} = bm\left( {1 - {x_3}\left( t \right)} \right) + p\mathit{\delta }{x_3}\left( t \right) - \frac{{\beta {x_1}\left( t \right){x_3}\left( t \right)}}{{1 + \alpha {x_3}\left( t \right)}} - b{x_1}\left( t \right) \buildrel \Delta \over = {f_1},\\ \frac{{{{\rm{d}}}{\mathit{x}_2}\left( t \right)}}{{{{\rm{d}}}\mathit{t}}} = \frac{{\beta {x_1}\left( t \right){x_3}\left( t \right)}}{{1 + \alpha {x_3}\left( t \right)}} - \left( {b + \omega + \varepsilon } \right){x_2}\left( t \right) \buildrel \Delta \over = {f_2},\\ \frac{{{{\rm{d}}}{\mathit{x}_3}\left( t \right)}}{{{{\rm{d}}}\mathit{t}}} = \omega {x_2}\left( t \right) - p\mathit{\delta }{x_3}\left( t \right) - \mathit{\gamma }{x_3}\left( t \right) - \frac{{\xi {x_3}\left( t \right)}}{{1 + k{x_3}\left( t \right)}} \buildrel \Delta \over = {f_3}. \end{array} \right. $ (6)

下面证明式(6) 在R0=1处会出现后向分支.已知无病平衡点在(P0, ξ)上, 且无病平衡点的局部稳定性在点(P0, ξ*)处发生改变, 其中:$ {\xi ^*} = \frac{{\beta \omega m-(p\delta + \gamma )(b + \omega + \varepsilon )}}{{b + \omega + \varepsilon }}$, ξ>ξ*时,R0 < 1;ξ < ξ*时,R0>1;当ξ=ξ*时,平衡点P0处的线性化矩阵为$ \mathit{\boldsymbol{M}}\left( {{P_0}, {\xi ^*}} \right) = \left[{\begin{array}{*{20}{c}} {-b}&0&{-bm-\beta m + p\delta }\\ 0&{ - (b + \omega + \varepsilon )}&{\beta m}\\ 0&\omega &{ - (p\delta + \gamma + {\xi ^*})} \end{array}} \right] $,它的特征值为λ1=-bλ2=-(b+ω+ε++γ+ξ),λ3=0,显然0为单重特征值,且其他特征值都是负实数, 所以文献[5]中定理4.1的假设A1成立.

w=(w1, w2, w3)T为与λ3=0相应的右特征向量, v=(v1, v2, v3)为左特征向量, 其中v·w=1,则

$ \left[ {\begin{array}{*{20}{c}} { - b}&0&{ - bm - \beta m + p\delta }\\ 0&{ - \left( {b + \omega + \varepsilon } \right)}&{\beta m}\\ 0&\omega &{ - \left( {p\delta + \gamma + {\xi ^*}} \right)} \end{array}} \right]\left[ \begin{array}{l} {w_1}\\ {w_2}\\ {w_3} \end{array} \right] = 0;\\\left[ {\begin{array}{*{20}{c}} {{v_1}},&{{v_2}},&{{v_3}} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} { - b}&0&{ - bm - \beta m + p\delta }\\ 0&{ - \left( {b + \omega + \varepsilon } \right)}&{\beta m}\\ 0&\omega &{ - \left( {p\delta + \gamma + {\xi ^*}} \right)} \end{array}} \right] = 0, $ (7)
$ {v_1}{w_1} + {v_2}{w_2} + {v_3}{w_3} = 1. $ (8)

由式(7) 和(8) 计算得$ \mathit{\boldsymbol{w}} = {(p\delta-bm-\beta m, \frac{{b\beta m}}{{b + \omega + \varepsilon }}, b)^{\rm{T}}} $, $ \mathit{\boldsymbol{v}} = (0, \frac{{\omega (b + \omega + \varepsilon )}}{{b\beta \omega m + b{{(b + \omega + \varepsilon )}^2}}}, \frac{{{{(b + \omega + \varepsilon )}^2}}}{{b\beta \omega m + b{{(b + \omega + \varepsilon )}^2}}}) $. f1, f2, f3在平衡点处的偏导数为: $ \frac{{{\partial ^2}{f_1}}}{{\partial {x_1}\partial {x_3}}} = \frac{{{\partial ^2}{f_1}}}{{\partial {x_3}\partial {x_1}}} =-\beta $$ \frac{{{\partial ^2}{f_2}}}{{\partial {x_1}\partial {x_3}}} = \frac{{{\partial ^2}{f_2}}}{{\partial {x_3}\partial {x_1}}} = \beta $$\frac{{{\partial ^2}{f_3}}}{{\partial {x_3}\partial {x_3}}} = 2k\xi $$ \frac{{{\partial ^2}{f_3}}}{{\partial \xi \partial {x_3}}} = \frac{{{\partial ^2}{f_3}}}{{\partial {x_3}\partial \xi }} = 1 $.由文献[5]中定理4.1可知$ {a_1} = 2{v_1}{w_1}{w_3}\frac{{{\partial ^2}{f_1}}}{{\partial {x_1}\partial {x_3}}} + 2{v_2}{w_1}{w_3}\frac{{{\partial ^2}{f_2}}}{{\partial {x_1}\partial {x_3}}} + {v_3}w_{_3}^{^2}\frac{{{\partial ^2}{f_3}}}{{\partial {x_3}\partial {x_3}}} $$ = \frac{{2(b + \omega + \varepsilon )[\beta \omega p\delta + bk\xi (b + \omega + \varepsilon )-\beta \omega m(b + \beta )]}}{{\beta \omega m + {{(b + \omega + \varepsilon )}^2}}} $${a_2} = {v_3}{w_3}\frac{{{\partial ^2}{f_3}}}{{\partial {x_3}\partial \xi }} = \frac{{{{(b + \omega + \varepsilon )}^2}}}{{\beta \omega m + {{(b + \omega + \varepsilon )}^2}}} $.显然a2>0,令$ {R_1} = \frac{{\beta \omega p\delta + bk\xi (b + \omega + \varepsilon )}}{{\beta \omega m(b + \beta )}} $, 则当R1 < 1时a1 < 0;当R1>1时a1>0.由上面分析可以得到定理4.

定理4  若R1>1,系统(2) 在R0=1处会出现后向分支;若R1 < 1,系统(2) 在R0=1处会出现前向分支.(以ξ为参数的分支图见图 2)

图 2 ξ为分支参数的后向分支图像 Figure 2 The backward bifurcation diagram of I1 and I2 versus ξ
4 全局稳定性

定理5  当R0 < R1* < 1时无病平衡点P0是全局渐近稳定的,其中R1*=βωm/(b+ω+ε)(+γ).

证明  由文献[6]引理1.2可知,选择序列tk→∞, τk→∞,(k→∞),使得E(tk)→EI(Tk)→I, $ \frac{{{{{\rm{d}}}}E({t_k})}}{{{{{\rm{d}}}}{t_k}}} \to 0 $$ \frac{{{{{\rm{d}}}}I({\tau _k})}}{{{{{\rm{d}}}}{\tau _k}}} \to 0 $.由系统(2) 第2个式子可知

$ {E^\infty } = \frac{\mathit{\beta }}{{b + \omega + \varepsilon }}\mathop {\lim }\limits_{k \to \infty } \frac{{SI\left( {{\mathit{\tau }_k}} \right)}}{{1 + \alpha I\left( {{\mathit{\tau }_k}} \right)}} \le \frac{{\mathit{\beta }m}}{{b + \omega + \varepsilon }}{I^\infty }. $ (9)

$ \frac{{{{{\rm{d}}}}I}}{{{{{\rm{d}}}}t}} = \omega E-p\delta I-\gamma I-\frac{{\xi I}}{{1 + kI}} = 0 $,则(+γ)kI2+(+γ+ξ-ωkE)I-ωE=0.由式(2) 的第3个式子可得

$ \begin{array}{*{20}{l}} {I = \frac{{\omega kE - \left( {p\delta + \gamma + \xi } \right) \pm \sqrt {{{\left( {p\delta + \gamma + \xi - \omega kE} \right)}^2} + 4\left( {p\delta + \gamma } \right)k\omega E} }}{{2\left( {p\delta + \gamma } \right)k}} \le }\\ {\frac{{\omega kE - \left( {p\delta + \gamma + \xi } \right) + \sqrt {{{\left( {p\delta + \gamma + \xi - \omega kE} \right)}^2} + 4\left( {p\delta + \gamma + \xi } \right)k\omega E} }}{{2\left( {p\delta + \gamma } \right)k}} = \frac{{\omega E}}{{\left( {p\mathit{\delta } + \gamma } \right)}}.} \end{array} $

由此可得$ {I^\infty } \le \frac{{\omega {E^\infty }}}{{p\delta + \gamma }} $,再结合(9) 式得$ {E^\infty } \le \frac{{\beta m\omega }}{{(b + \omega + \varepsilon )(p\delta + \gamma )}}{E^\infty } = R_{_1}^{^*}{E^\infty } $${I^\infty } \le \frac{{\beta m\omega }}{{(b + \omega + \varepsilon )(p\delta + \gamma )}}{I^\infty } = R_1^{^*}{I^\infty } $.

因为R1*≤1,所以E≤0, I≤0,这与已知E≥0,I≥0矛盾, 所以E=E=0, I=I=0,即$ \mathop {\lim }\limits_{t \to \infty } E\left( t \right) = 0$, $ \mathop {\lim }\limits_{t \to \infty } I\left( t \right) = 0$,从而得到$ \mathop {\lim }\limits_{t \to \infty } S\left( t \right) = m $.结合P0的局部稳定性得,当R0 < R1* < 1时,无病平衡点P0是全局渐近稳定的.

下面讨论当1 < R1*时,地方病平衡点的全局稳定性.当1 < R1*时系统(2) 可能会出现两个地方病平衡点, 且可能出现双稳性.令BR2内的欧氏单位球,且B∂B分别为闭包与边界.令Lip(XY)为从XY的李普希兹函数的集合, φLip(BD)是单连通的且可求积分的曲面,其中DRnψLip(∂BD)是可求长的闭曲线, 且如果是一一映射, 则可以称之为简单闭曲线.如果ψ看作是函数φBD限制在∂B上的函数,则可以记为ψ=φ|∂B,令Σ(ψD)={φLip(BD):ψ=φ|∂B},如果D是单连通的开集, 则Σ(ψD)是非空的[7].令‖·‖为$ {{\bf{R}}^{\left( \begin{smallmatrix} \rm{n} \\ 2 \end{smallmatrix} \right)}} $上的范数, 定义一个在集合D上的函数S, 且$ S\varphi ={{\int }_{B}}\|\mathit{\boldsymbol{P}}\cdot (\frac{\partial \varphi }{\partial {{u}_{1}}}\wedge \frac{\partial \varphi }{\partial {{u}_{2}}})\|{{\rm{d}}}u $, 其中u=(u1, u2),uφ(u)是B上的李普希兹函数; $ \frac{\partial \varphi }{\partial {{u}_{1}}}\wedge \frac{\partial \varphi }{\partial {{u}_{2}}} $$ {{\bf{R}}^{\left( \begin{smallmatrix} \rm{n} \\ 2 \end{smallmatrix} \right)}} $上的向量; P$ \left( {\begin{array}{*{20}{c}} {\rm{n}}\\ 2 \end{array}} \right) \times \left( {\begin{array}{*{20}{c}} {\rm{n}}\\ 2 \end{array}} \right) $矩阵, 且‖P-1‖在φ(B)上有界.

引理3[8]  设ψRn上是可求长的简单闭曲线, 则存在σ>0, 使得对任意的φΣ(ψRn), 都有σ.

xf(x)∈RnxDRn,是一阶连续可微的函数.考虑自治微分方程

$ \frac{{{{\rm{d}}}x}}{{{{\rm{d}}}t}} = f\left( x \right). $ (10)

对任意曲面φ(u), 可以定义新的曲面φt(u)=x(t, φ(u)).如果把φt(u)看作是关于u的函数,则曲面φt(u)表示在t时刻由式(10) 所确定的映射, 如果把φt(u)看作是关于t的函数,则曲面φt(u)表示方程(10) 通过初始点(0,φ(u))时的解.由文献[7]将t的右导数记为$ {D_ + }\;S{\varphi _t} = {\smallint _{\bar B}}\mathop {{\rm{lim}}}\limits_{h \to {0^ + }} \frac{1}{h}(\left\| {z + h\mathit{\boldsymbol{Q}}({\varphi _t}\left( u \right))\mathit{\boldsymbol{z}}} \right\|-\left\| \mathit{\boldsymbol{z}} \right\|){{{\rm{d}}}}u $,其中:$ \mathit{\boldsymbol{Q}} = {\mathit{\boldsymbol{P}}_f}{\mathit{\boldsymbol{P}}^{- 1}} + \mathit{\boldsymbol{P}}\frac{{\partial {f^{^{[2]}}}}}{{\partial x}}{\mathit{\boldsymbol{P}}^{ -1}} $PfP沿f方向的方向导数. $ \frac{{\partial {f^{^{[2]}}}}}{{\partial x}} $$ \frac{{\partial f}}{{\partial x}} $的第二加性复合矩阵, $\mathit{\boldsymbol{z}} = \mathit{\boldsymbol{P}}\cdot(\frac{{\partial \varphi }}{{\partial {u_1}}} \wedge \frac{{\partial \varphi }}{{\partial {u_2}}}) $是微分方程$ \frac{{{{{\rm{d}}}}\mathit{\boldsymbol{z}}}}{{{{{\rm{d}}}}t}} = \mathit{\boldsymbol{Q}}({\varphi _t}\left( u \right))\mathit{\boldsymbol{z}} $的解, 所以$ {D_ + }S{\varphi _t} = {\smallint _{\bar B}}{D_ + }\left\| \mathit{\boldsymbol{z}} \right\|{{{\rm{d}}}}u $.系统(2) 在点P=(S, E, I)处的雅可比矩阵J与其第二加性复合矩阵分别为

$ \mathit{\boldsymbol{J}} = \left[ {\begin{array}{*{20}{c}} { - \left( {\frac{{\beta I}}{{1 + \alpha I}} + b} \right)}&0&{ - bm - \frac{{\beta S}}{{{{\left( {1 + \alpha I} \right)}^2}}} + p\delta }\\ {\frac{{\beta I}}{{1 + \alpha I}}}&{ - \left( {b + \omega + \varepsilon } \right)}&{\frac{{\beta S}}{{{{\left( {1 + \alpha I} \right)}^2}}}}\\ 0&\omega &({ - p\delta {\rm{ + }}\gamma {\rm{ + }}\frac{\xi }{{{{\left( {1 + kI} \right)}^2}}}}) \end{array}} \right],\\{\mathit{\boldsymbol{J}}^{\left[ 2 \right]}} = \left[ {\begin{array}{*{20}{c}} { - \left( {\frac{{\beta I}}{{1 + \alpha I}} + b + {F_2}} \right)}&{\frac{{\beta S}}{{{{\left( {1 + \alpha I} \right)}^2}}}}&{bm - p\delta + \frac{{\beta S}}{{{{\left( {1 + \alpha I} \right)}^2}}}}\\ \omega &{ - \left( {\frac{{\beta I}}{{1 + \alpha I}} + b + {F_1}} \right)}&0\\ 0&{\frac{{\beta S}}{{1 + \alpha I}}}&{ - \left( {{F_1} + {F_2}} \right)} \end{array}} \right]. $

其中:$ {F_1} = p\delta + \gamma + \frac{\xi }{{{{(1 + k{I_1})}^2}}} $F2=b+ω+ε.令$\mathit{\boldsymbol{P}} = \frac{1}{I}\mathit{\boldsymbol{\tilde E}} $,其中$ \mathit{\boldsymbol{\tilde E}} $为单位矩阵, $ {\mathit{\boldsymbol{P}}_f}{\mathit{\boldsymbol{P}}^{-1}} =-\frac{1}{I}\frac{{{{{\rm{d}}}}I}}{{{{{\rm{d}}}}t}}\mathit{\boldsymbol{\tilde E}} $,整理得$ {\mathit{\boldsymbol{P}}_f}{\mathit{\boldsymbol{P}}^{-1}} = {\rm{diag}}(p\delta + \gamma + \frac{\xi }{{1 + kI}}-\frac{{\omega E}}{I}, $$ p\delta + \gamma + \frac{\xi }{{1 + kI}}-\frac{{\omega E}}{I}, p\delta + \gamma + \frac{\xi }{{1 + kI}}-\frac{\omega }{{EI}}) $,所以$ \mathit{\boldsymbol{Q}} = {\mathit{\boldsymbol{P}}_f}{\mathit{\boldsymbol{P}}^{-1}} + \mathit{\boldsymbol{P}}\frac{{\partial {f^2}}}{{\partial x}}{\mathit{\boldsymbol{P}}^{-1}} = \left( {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}}&{{a_{13}}}\\ {{a_{21}}}&{{a_{22}}}&{{a_{23}}}\\ {{a_{31}}}&{{a_{32}}}&{{a_{33}}} \end{array}} \right) $,其中: $ {a_{11}} =-(\frac{{\beta I}}{{1 + \alpha I}} + 2b + \omega + \varepsilon + \frac{{\omega E}}{I}) + p\delta + \gamma + \frac{\xi }{{1 + kI}} $; $ {a_{12}} = \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} $; ${a_{13}} = bm-p\delta + \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} $; a21=ω; $ {a_{22}} =-(\frac{{\beta I}}{{1 + \alpha I}} + b + \frac{{\omega E}}{I}) + \frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}} $; a23=0; a31=0; $ {a_{32}} = \frac{{\beta I}}{{1 + \alpha I}} $; $ {a_{33}} =-\left( {b + \omega + \varepsilon + \frac{{\omega E}}{I}} \right) + \frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}} $.令z=(z1, z2, z3)T$ \left\| \mathit{\boldsymbol{z}} \right\| = \left\{ \begin{array}{l} {\rm{max}}\{ \left| {{z_1}} \right| + \left| {{z_3}} \right|, \left| {{z_2}} \right| + \left| {{z_3}} \right|\}, 0 \le {z_2}{z_3}, \\ {\rm{max}}\{ \left| {{z_1}} \right| + \left| {{z_3}} \right|, \left| {{z_2}} \right|\}, {z_2}{z_3} \le 0. \end{array} \right. $

定理6  存在η>0使得D+z‖≤-ηz‖ (zR3; S, E, I>0;D+z‖是‖z‖的右导数, z

$ \frac{{{{{\rm{d}}}}\mathit{\boldsymbol{z}}}}{{{{{\rm{d}}}}t}} = \mathit{\boldsymbol{Qz}} $的解).其中max{ω+ξ-b, βm++γ+ξ-b-ω-ε, (b+β)m+ξ--b-ω-ε} < -η.

证明  易知, 如果不等式对z成立, 那么对-z也成立, 下面分情况进行讨论.

1) 当0 < z1, z2, z3且|z1|+|z3|>|z2|+|z3|时, ‖z‖=|z1|+|z3|,${D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(|{z_1}| + |{z_3}|) = {D_ + }(|{z_1}| + |{z_3}|) = \frac{{{{{\rm{d}}}}{z_1}}}{{{{{\rm{d}}}}t}} + \frac{{{{{\rm{d}}}}{z_3}}}{{{{{\rm{d}}}}t}} = $$ (-(\frac{{\beta I}}{{1 + \alpha I}} + 2b + \omega + \varepsilon + \frac{{\omega E}}{I}) + p\delta + \gamma + \frac{\xi }{{1 + kI}}){z_1} + $$ (\frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} + \frac{{\beta I}}{{1 + \alpha I}}){z_2} + (bm + \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} + \frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}} $$ -(p\delta + b + \omega + \varepsilon + \frac{{\omega E}}{I})){z_3} < \max \{ \beta m + p\delta + \gamma + \xi-\left( {2b + \omega + \varepsilon + \frac{{\omega E}}{I}} \right), $$ \left( {b + \beta } \right)m + \xi-(p\delta + b + \omega + \varepsilon + \frac{{\omega E}}{I})\} \left\| \mathit{\boldsymbol{z}} \right\| $.

2) 当0 < z1, z2, z3且|z1|+|z3| < |z2|+|z3|时, ‖z‖=|z2|+|z3|,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(|{z_2}| + |{z_3}|) = {D_ + }({z_2} + {z_3}) = \frac{{{{{\rm{d}}}}{z_2}}}{{{{{\rm{d}}}}t}} + \frac{{{{{\rm{d}}}}{z_3}}}{{{{{\rm{d}}}}t}} = \omega {z_1} + $$ (\frac{\xi }{{kI{{\left( {1 + kI} \right)}^2}}}-\frac{{\omega E}}{I}-b){z_2} + (\xi kI{\left( {1 + kI} \right)^2}-\frac{{\omega E}}{I} - b - \omega - \varepsilon ) $$ {z_3} < \max \{ \omega + \xi-\frac{{\omega E}}{I}-b, \xi-\frac{{\omega E}}{I} - b - \omega - \varepsilon \} \left\| \mathit{\boldsymbol{z}} \right\| = \left( {\omega + \xi - \frac{{\omega E}}{{I - b}}} \right)\left\| \mathit{\boldsymbol{z}} \right\|$.

3) 当z1 < 0 < z2, z3, 且|z1|+|z3|>|z2|+|z3|时,则‖z‖=|z1|+|z3|,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(\left| {{z_1}} \right| + \left| {{z_3}} \right|) = {D_ + }(-{z_1} + {z_3}) =-\frac{{{{{\rm{d}}}}{z_1}}}{{{{{\rm{d}}}}t}} + \frac{{{{{\rm{d}}}}{z_3}}}{{{{{\rm{d}}}}t}} = $$ (-(\frac{{\beta I}}{{1 + \alpha I}} + 2b + \omega + \varepsilon + \frac{{\omega E}}{I}) + (p\delta + \gamma + \frac{\xi }{{1 + kI}})){z_1} + (\frac{{\beta I}}{{1 + \alpha I}}-$$ \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}}){z_2} + (p\delta + \frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-(bm + \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} + b + \frac{{\omega E}}{I} + \omega + \varepsilon ))$$\left| {{z_3}} \right| < \max \{ p\delta + \gamma + \xi-\left( {2b + \omega + \varepsilon + \frac{{\omega E}}{I}} \right), p\delta + \xi-(bm + \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} $$ + b + \frac{{\omega E}}{I} + \omega + \varepsilon )\} \left\| \mathit{\boldsymbol{z}} \right\| < (p\delta + \gamma + \xi-(b + \omega + \varepsilon + \frac{{\omega E}}{I}))\left\| \mathit{\boldsymbol{z}} \right\| $.

4) 当z1 < 0 < z2, z3且|z1|+|z3|… < |z2|+|z3|时,‖z‖=|z2|+|z3|,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(\left| {{z_2}} \right| + \left| {{z_3}} \right|) = {D_ + }({z_2} + {z_3}) = \frac{{{{{\rm{d}}}}{z_2}}}{{{{{\rm{d}}}}t}} + \frac{{{{{\rm{d}}}}{z_3}}}{{{{{\rm{d}}}}t}} =-\omega \left| {{z_1}} \right| + (\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}- $$(b + \frac{{\omega E}}{I}))\left| {{z_2}} \right| + (\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-(b + \frac{{\omega E}}{I} + \omega + \varepsilon ))\left| {{z_3}} \right| < (\xi-b-\frac{{\omega E}}{I})\left\| \mathit{\boldsymbol{z}} \right\| $.

5) 当z2 < 0 < z1, z3, 且|z1|+|z3|>|z2|时, ‖z‖=|z1|+|z3|,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(\left| {{z_1}} \right| + \left| {{z_3}} \right|) = {D_ + }({z_1} + {z_3}) = \frac{{{{{\rm{d}}}}{z_1}}}{{{{{\rm{d}}}}t}} + \frac{{{{{\rm{d}}}}{z_3}}}{{{{{\rm{d}}}}t}}, $$ = (-(\frac{{\beta I}}{{1 + \alpha I}} + 2b + \omega + \varepsilon + \frac{{\omega E}}{I}) + p\delta + \gamma + \frac{\xi }{{1 + kI}}){z_1} $$ -(\frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} + \frac{{\beta I}}{{1 + \alpha I}})\left| {{z_2}} \right| + (bm + \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} + \frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-(p\delta $$ + b + \frac{{\omega E}}{I} + \omega + \varepsilon ))\left| {{z_3}} \right| < \max \{ p\delta + \gamma + \xi-2b-\omega-\varepsilon - \frac{{\omega E}}{I}, $$\left( {b + \beta } \right)m + \xi-p\delta-b-\omega - \varepsilon - \frac{{\omega E}}{I}\} \left\| \mathit{\boldsymbol{z}} \right\| $.

6) 当z2 < 0 < z1, z3且|z1|+|z3| < |z2|时, ‖z‖=|z2|,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(\left| {{z_2}} \right|) = {D_ + }(-{z_2}) =-\frac{{{{{\rm{d}}}}{z_2}}}{{{{{\rm{d}}}}t}}{\rm{ }} = $$-\omega {z_1}-(\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-\frac{{\beta I}}{{1 + \alpha I}} - \frac{{\omega E}}{I} - b) $$ {z_2} < (\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-\frac{{\beta I}}{{1 + \alpha I}}-\frac{{\omega E}}{I}-b)\left| {{z_2}} \right| < (\xi - \frac{{\beta I}}{{1 + \alpha I}} - \frac{{\omega E}}{I} - b)\left\| \mathit{\boldsymbol{z}} \right\| $.

7) 当z3 < 0 < z1, z2, 且|z1|+|z3|>|z2|时, ‖z‖=|z1|+|z3|,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(\left| {{z_1}} \right| + \left| {{z_3}} \right|) = {D_ + }({z_1}-{z_3}) = \frac{{{{{\rm{d}}}}{z_1}}}{{{{{\rm{d}}}}t}}-\frac{{{{{\rm{d}}}}{z_3}}}{{{{{\rm{d}}}}t}} = (-(\frac{{\beta I}}{{1 + \alpha I}} + 2b + $$ \omega + \varepsilon + \frac{{\omega E}}{I}) + p\delta + \gamma + \frac{\xi }{{1 + kI}})\left| {{z_1}} \right| + (\frac{{\beta S}}{{{{(1 + \alpha I)}^2}}}-\frac{{\beta I}}{{1 + \alpha I}})\left| {{z_2}} \right| + (\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}} + p\delta-(bm + $$ \frac{{\beta S}}{{{{(1 + \alpha I)}^2}}} + b + \frac{{\omega E}}{I} + \omega + \varepsilon ))\left| {{z_3}} \right| < (\beta m + p\delta + \gamma + \xi-b-\omega-\varepsilon - \frac{{\omega E}}{I})\left\| \mathit{\boldsymbol{z}} \right\| $.

8) 当z3 < 0 < z1, z2, 且|z1|+|z3| < |z2|时, ‖z‖=‖z2‖,$ {D_ + }\left\| \mathit{\boldsymbol{z}} \right\| = {D_ + }(\left| {{z_2}} \right|) = {D_ + }({z_2}) = \frac{{{{{\rm{d}}}}{z_2}}}{{{{{\rm{d}}}}t}} = \omega {z_1} + (\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-\frac{{\beta I}}{{1 + \alpha I}}-\frac{{\omega E}}{I} $$ -b){z_2} = \omega \left| {{z_1}} \right| + (\frac{{\xi kI}}{{{{\left( {1 + kI} \right)}^2}}}-\frac{{\beta I}}{{1 + \alpha I}}-\frac{{\omega E}}{I} - b)\left| {{z_2}} \right| < (\omega - b - \frac{{\omega E}}{I})\left\| \mathit{\boldsymbol{z}} \right\| $.

以上8中情况都有D+z‖≤-ηz‖,zR3.

定理7  [9]ψΩ内简单闭曲线, 则存在τ>0和的极小化序列{φk}, 其中φΣ(ψΩ),使得对任意k=1, 2, 3, …,t∈[0, τ], 都有{φtk}⊂Ω.

由定理6和定理7可以得到定理8和定理9.

定理8[9]  系统(2) 在Ω内的任意ω极限点都是平衡点, 且在Ω内所有正半轨线都趋于某个平衡点.

定理9[9]  若max{ω+ξ-b, βm++γ+ξ-b-ω-ε, (b+β)m+ξ--b-ω-ε} < -η成立, 则可以得到下面结论:1) 如果系统没有地方病平衡点, 则系统(2) 所有的解都趋于无病平衡点.

2) 当R0>1时, 如果E(0)>0, 则系统(2) 的所有解都趋于地方病平衡点P2.

3) 当R0 < 1时, 如果存在两个地方病平衡点, 则系统(2) 的所有解要么趋于无病平衡点, 要么趋于地方病平衡点P2.

5 结论

本文经过研究发现系统在R0=1处会出现后向分支, 且后向分支的出现会使系统可能出现双稳性.若取ξ为分支参数,则当a1>0, a2>0时出现后向分支; 当a1 < 0, a2>0时出现前向分支.又因为∂a1/∂ξ>0, 所以系统出现后向分支的可能性随着ξ的增加而增加.还得到当R0 < R0* < 1时, 传染病会逐渐消失, 否则传染病会一直存在, 所以我们要采取一切措施减小基本再生数, 通过分析可知增大ξm′的值可以减小基本再生数.

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