近年来分数阶微分方程(Fractional Differential Equation, FDEs)的应用越来越普遍,如模拟反常扩散过程、波传播、湍流、生物系统等[1-2]。目前除了少数简单的FDEs外,大部分FDEs还不能找到其解析解[3]。因此,针对FDEs提出简单高效的数值算法是十分必要的。
求解分数阶微分方程的数值算法主要包括有限差分法、有限元法、级数逼近法(变分迭代法、Adomian分解法、同伦摄动法等)、移动网格法、矩阵转化法等。有限差分法[4-5]、有限元法[6-7]将方程离散化,从而得到方程的近似数值解。与它们相比,变分迭代法(Variational Iteration Method, VIM)不需要进行变换和数值逼近,是一种重要的近似解析方法。1978年,Inokuti等[8]提出广义拉格朗日乘子法(Lagrange Multiplier, LM)。基于LM方法,何吉欢[9]于1997年提出了VIM方法。目前,VIM方法已广泛应用于非线性微分方程的近似逼近问题。尹伟石等[10]应用VIM方法求解Riesz分数阶偏微分方程。基于VIM方法,高秀丽等[11]成功模拟了Whitham-Broer-Kaup方程和mKdV方程两类非线性数学物理方程的行波解。姜兆敏等[12]用VIM求解二阶常微分方程组边值问题,并给出2个具体应用实例。
许多数学家和生态学家对捕食者−食饵(Predator-Prey, P-P)系统进行了深入的研究,建立了一系列数学模型,如Volterra模型、带自身阻滞作用logistic项的改进Volterra模型、Lotlak-Volterra模型等。分数阶微积分的非局部性质使其在模拟遗传性和记忆性现象上更具优势。因此,分数阶P-P模型越来越受到研究者的关注。El-Shahed等[13]研究了一类分数阶广义P-P模型的正平衡点的存在性、稳定性和极限环。王虎等[14]讨论了具有阶段结构的时滞分数阶P-P模型的稳定性,得到了平衡点的渐进稳定性条件和参数稳定区间。关于P-P模型的VIM方法研究,汪维刚等[15]利用一组泛函,选取拉格朗日乘子,用修正的变分方法,得到了相应模型的近似解。但是其并未对VIM迭代格式进行收敛性分析。由于分数阶模型的VIM方法研究相对较少,本文研究式(1)~(2)的分数阶捕食者−食饵模型的VIM方法及其收敛性。
$ {}_0^{\rm{C}}D_t^\alpha u{\text{(}}t{\text{) = }}{r_1}u\left( {1 - \frac{u}{{{N_1}}} - {\sigma _1}\frac{v}{{{N_2}}}} \right) \text{,} 0 \leqslant t \leqslant T $ | (1) |
$ {}_0^{\rm{C}}D_t^\beta v{\text{(}}t{\text{) = }}{r_2}v\left( { - 1 + {\sigma _2}\frac{u}{{{N_1}}} - \frac{v}{{{N_2}}}} \right) \text{,} 0 \leqslant t \leqslant T $ | (2) |
式(1)~(2)中:u和v分别为捕食者和食饵的种群密度,t为时间,T是t的最大时间。
$ {}_0^{\rm{C}}D_t^\theta w(t) = \frac{1}{{\varGamma ({\text{2}} - \theta )}}\int_0^t {\frac{{{w^{\left( 2 \right)}}(\tau )}}{{{{(t - \tau )}^{\theta - 1}}}}} {\text{d}}\tau \text{,} \theta \in \left( {1,2} \right) $ |
式中:Γ是Gamma函数,τ为积分运算变量。
为了将
$ {J^{\theta - 1}}{}_0^{\rm{C}}D_t^\theta w(t){\text{ = }}w^{\prime}{\text{}}(t) - w^{\prime}{\text{}}(0) $ | (3) |
式中:
$ {J^{\theta - 1}}f(t) = \frac{1}{{\varGamma \left( {\theta - 1} \right)}}\int_0^t {{{(t - \tau )}^{\theta - 2}}f(\tau )} {\text{d}}\tau $ |
由式(3)可得式(1)~(2)的等价模型为
$ u^{\prime}{\text{(}}t{\text{)}} - u^{\prime}{\text{(0)}} - {J^{\alpha - 1}}F{\text{(}}u,v{\text{)}} = 0 $ | (4) |
$ v^{\prime}{\text{(}}t{\text{)}} - v^{\prime}{\text{(0)}} + {J^{\beta - 1}}G{\text{(}}u,v{\text{)}} = 0 $ | (5) |
式中:
$ F{\text{(}}u,v{\text{)}} = {r_1}u - \frac{{{r_1}}}{{{N_1}}}{u^{\text{2}}} - \frac{{{r_1}{\sigma _1}}}{{{N_2}}}uv $ |
$ G{\text{(}}u,v{\text{)}} = {r_2}v - \frac{{{r_2}{\sigma _2}}}{{{N_1}}}uv + \frac{{{r_2}}}{{{N_2}}}{v^2} $ |
假设
$ \begin{array}{*{20}{c}}\left| {F{\text{(}}u,v{\text{)}} - F{\text{(}}\tilde u,v{\text{)}}} \right| \leqslant C\left| {u - \tilde u} \right| \\ \left| {F{\text{(}}u,v{\text{)}} - F{\text{(}}u,\tilde v{\text{)}}} \right| \leqslant C\left| {v - \tilde v} \right| \\ \left| {G{\text{(}}u,v{\text{)}} - G{\text{(}}\tilde u,v{\text{)}}} \right| \leqslant C\left| {u - \tilde u} \right| \\ \left| {G{\text{(}}u,v{\text{)}} - G{\text{(}}u,\tilde v{\text{)}}} \right| \leqslant C\left| {v - \tilde v} \right| \end{array}$ |
对模型(4)~(5)构造式(6)~(7)的限制泛函。
$ \begin{gathered} {u_{n + 1}}{\text{(}}t{\text{)}} = {u_n}{\text{(}}t{\text{)}} + \hfill \int_0^t {{\lambda _1}{\text{(}}\tau {\text{)}}( {u_n^{\prime}{\text{(}}\tau {\text{)}} - u^{\prime}{\text{(0)}} - {J^{\alpha - 1}}\tilde F{\text{(}}{u_n},{v_n}{\text{)}}} ){\text{d}}\tau } \hfill \\ \end{gathered} $ | (6) |
$ \begin{gathered} {v_{n + 1}}{\text{(}}t{\text{)}} = {v_n}{\text{(}}t{\text{)}} + \hfill \int_0^t {{\lambda _{\text{2}}}{\text{(}}\tau {\text{)}}( {v_n^{{\prime}}{\text{(}}\tau {\text{)}} - v^{\prime}{\text{(0)}} + {J^{\beta - 1}}\tilde G{\text{(}}{u_n},{v_n}{\text{)}}} ){\text{d}}\tau } \hfill \\ \end{gathered} $ | (7) |
式(6)~(7)中:
$ {\text{δ}} {u_{n + 1}}{\text{(}}t{\text{)}} = {\text{δ}} {u_n}{\text{(}}t{\text{)}} + \int_0^t {{\lambda _{\text{1}}}{\text{(}}\tau {\text{)}} {\text{δ}} u_n^{{\prime}}{\text{(}}\tau {\text{)d}}\tau } = 0 $ |
$ {\text{δ}} {v_{n + 1}}{\text{(}}t{\text{)}} = {\text{δ}} {v_n}{\text{(}}t{\text{)}} + \int_0^t {{\lambda _{\text{2}}}{\text{(}}\tau {\text{)}} {\text{δ}} v_n^{{\prime}}{\text{(}}\tau {\text{)d}}\tau } = 0 $ |
解得
$ {\text{1}} + {\lambda _{\text{1}}}{\text{(}}\tau {\text{)}}{{\text{|}}_{\tau = t}} = 0 \text{,} \lambda _{\text{1}}^{{\prime}}{\text{(}}\tau {\text{)}} = 0 $ |
$ {\text{1}} + {\lambda _{\text{2}}}{\text{(}}\tau {\text{)}}{{\text{|}}_{\tau = t}} = 0 \text{,} \lambda _{\text{2}}^{{\prime}}{\text{(}}\tau {\text{)}} = 0 $ |
即
$ \begin{gathered} {u_{n + 1}}{\text{(}}t{\text{)}} = {u_n}{\text{(}}t{\text{)}} - \hfill \int_0^t {u_n^{{\prime}}{\text{(}}\tau {\text{)}} - u^{\prime}{\text{(0)}} - {J^{\alpha - 1}}F{\text{(}}{u_n},{v_n}{\text{)d}}\tau } \hfill \\ \end{gathered} $ | (8) |
$ \begin{gathered} {v_{n + 1}}{\text{(}}t{\text{)}} = {v_n}{\text{(}}t{\text{)}} - \hfill \int_0^t {v_n^{{\prime}}{\text{(}}\tau {\text{)}} - v^{\prime}{\text{(0)}} + {J^{\beta - 1}}G{\text{(}}{u_n},{v_n}{\text{)d}}\tau } \hfill \\ \end{gathered} $ | (9) |
定理1 取
证明 易知
$ \begin{array}{l}u\text{(}t\text{)}=u\text{(}t\text{)}- {\displaystyle {\int }_{0}^{t}u^{\prime}\text{(}\tau \text{)}-u^{\prime}\text{(0)}-{J}^{\alpha -1}F\text{(}u,v\text{)d}\tau }\end{array} $ |
$ \begin{gathered} v{\text{(}}t{\text{)}} = v{\text{(}}t{\text{)}} - \hfill \int_0^t {v^{\prime}{\text{(}}\tau {\text{)}} - v^{\prime}{\text{(0)}} + {J^{\beta - 1}}G{\text{(}}u,v{\text{)d}}\tau } \hfill \\ \end{gathered} $ |
记
$ \begin{gathered} {e_{n + 1}}{\text{(}}t{\text{)}} = {e_n}{\text{(}}t{\text{)}} - \hfill \int_0^t {e_n^{{\prime}}{\text{(}}\tau {\text{)}} - {J^{\alpha - 1}}\left( {{F{\text{(}}{u_n},{v_n}{\text{)}} - F{\text{(}}u,v{\text{)}}}} \right){\text{d}}\tau } \hfill \\ \end{gathered} $ | (10) |
$ \begin{gathered} {\varepsilon _{n + 1}}{\text{(}}t{\text{)}} = {\varepsilon _n}{\text{(}}t{\text{)}} - \hfill \int_0^t {\varepsilon _n^{{\prime}}{\text{(}}\tau {\text{)}} + {J^{\beta - 1}}\left( {G{\text{(}}{u_n},{v_n}{\text{)}} - G{\text{(}}u,v{\text{)}}} \right){\text{d}}\tau } \hfill \\ \end{gathered} $ | (11) |
显然有
$ {e_n}{\text{(0)}} = {\varepsilon _n}{\text{(0)}} = 0 $ | (12) |
计算可得
$\begin{split} {e_{n + 1}}{\text{(}}t{\text{)}} = & \hfill {e_n}{\text{(}}t{\text{)}} - \int_0^t {e_n^{{\prime}}{\text{(}}\tau {\text{)}} - {J^{\alpha - 1}}\left( {F{\text{(}}{u_n},{v_n}{\text{)}} - F{\text{(}}u,v{\text{)}}} \right){\text{d}}\tau } = \hfill \\ & {e_n}{\text{(0)}} + \int_0^t {{J^{\alpha - 1}}\left( {F{\text{(}}{u_n},{v_n}{\text{)}} - F{\text{(}}u,v{\text{)}}} \right){\text{d}}\tau } \hfill \\ \end{split}$ |
代入式(12),有
$ \begin{split} {e_{n + 1}}{\text{(}}t{\text{)}} = & \int_0^t {{J^{\alpha - 1}}\left( {F{\text{(}}{u_n},{v_n}{\text{)}} - F{\text{(}}u,{v_n}{\text{)}}} \right){\text{d}}\tau } + \hfill \\& \int_0^t {{J^{\alpha - 1}}\left( {F{\text{(}}u,{v_n}{\text{)}} - F{\text{(}}u,v{\text{)}}} \right){\text{d}}\tau } = \\ & \frac{1}{{\varGamma \left( {\alpha - 1} \right)}}\int_0^t \int_0^\tau {{{\text{(}}\tau - s{\text{)}}}^{\alpha - 2}}( F{\text{(}}{u_n},{v_n}{\text{)}} - F{\text{(}}u,{v_n}{\text{)}} ) {\text{d}}s{\text{d}}\tau + \hfill \\ & \frac{1}{{\varGamma \left( {\alpha - 1} \right)}}\int_0^t \int_0^\tau {{{\text{(}}\tau - s{\text{)}}}^{\alpha - 2}} ( F{\text{(}}u,{v_n}{\text{)}} - F{\text{(}}u,v{\text{)}} ) {\text{d}}s{\text{d}}\tau \hfill \\ \end{split} $ |
由Lipschitz条件,有
$ \begin{split} \left| {{e_{n + 1}}{\text{(}}t{\text{)}}} \right| \leqslant \hfill & \frac{C}{{\varGamma \left( {\alpha - 1} \right)}}\int_0^t {\int_0^\tau {{{{\text{(}}\tau - s{\text{)}}}^{\alpha - 2}}\left( {\left| {{e_n}{\text{(}}s{\text{)}}} \right| + \left| {{\varepsilon _n}{\text{(}}s{\text{)}}} \right|} \right)} {\text{d}}s{\text{d}}\tau } \leqslant \hfill \\ & \frac{C}{{\varGamma \left( {\alpha - 1} \right)}}\int_0^t \mathop {{\text{max}}}\limits_{0 \leqslant s \leqslant \tau } \left( {\left| {{e_n}{\text{(}}s{\text{)}}} \right| + \left| {{\varepsilon _n}{\text{(}}s{\text{)}}} \right|} \right) \int_0^\tau {{{{\text{(}}\tau - s{\text{)}}}^{\alpha - 2}}} {\text{d}}s{\text{d}}\tau \leqslant \hfill \\ & \frac{C}{{\varGamma \left( \alpha \right)}}\int_0^t {\mathop {{\text{max}}}\limits_{0 \leqslant s \leqslant \tau } \left( {\left| {{e_n}{\text{(}}s{\text{)}}} \right| + \left| {{\varepsilon _n}{\text{(}}s{\text{)}}} \right|} \right){\tau ^{\alpha - 1}}{\text{d}}\tau } \leqslant \hfill \\ & \frac{{C{T^{\alpha - 1}}}}{{\varGamma \left( \alpha \right)}}\int_0^t {\mathop {{\text{max}}}\limits_{0 \leqslant s \leqslant \tau } \left( {\left| {{e_n}{\text{(}}s{\text{)}}} \right| + \left| {{\varepsilon _n}{\text{(}}s{\text{)}}} \right|} \right){\text{d}}\tau } \hfill \\ \end{split} $ |
同理,可得
$ \left| {{\varepsilon _{n + 1}}{\text{(}}t{\text{)}}} \right| \leqslant \frac{{C{T^{\beta - 1}}}}{{\varGamma \left( \beta \right)}}\int_0^t {\mathop {{\text{max}}}\limits_{0 \leqslant s \leqslant \tau } \left( {\left| {{e_n}{\text{(}}s{\text{)}}} \right| + \left| {{\varepsilon _n}{\text{(}}s{\text{)}}} \right|} \right){\text{d}}\tau } $ |
综上,有
$ \left| {{e_{n + 1}}{\text{(}}t{\text{)}}} \right| + \left| {{\varepsilon _{n + 1}}{\text{(}}t{\text{)}}} \right| \leqslant C\left( {\frac{{{T^{\alpha - 1}}}}{{\varGamma \left( \alpha \right)}} + \frac{{{T^{\beta - 1}}}}{{\varGamma \left( \beta \right)}}} \right) \int_0^t {\mathop {{\text{max}}}\limits_{0 \leqslant s \leqslant \tau } \left( {\left| {{e_n}{\text{(}}s{\text{)}}} \right| + \left| {{\varepsilon _n}{\text{(}}s{\text{)}}} \right|} \right){\text{d}}\tau } $ |
记
$ \begin{split} & {\left\| {{E_{n + 1}}{\text{(}}T{\text{)}}} \right\|_\infty } \leqslant C\left( {\frac{{{T^{\alpha - 1}}}}{{\varGamma \left( \alpha \right)}} + \frac{{{T^{\beta - 1}}}}{{\varGamma \left( \beta \right)}}} \right)\int_0^T {{{\left\| {{E_n}{\text{(}}{\xi _1}{\text{)}}} \right\|}_\infty }{\text{d}}{\xi _1}} \leqslant \hfill \\& {C^{\text{2}}}{\left( {\frac{{{T^{\alpha - 1}}}}{{\varGamma \left( \alpha \right)}} + \frac{{{T^{\beta - 1}}}}{{\varGamma \left( \beta \right)}}} \right)^{\text{2}}}\int_0^T {\int_0^{{\xi _1}} {{{\left\| {{E_{n - 1}}{\text{(}}{\xi _2}{\text{)}}} \right\|}_\infty }} {\text{d}}{\xi _2}{\text{d}}{\xi _1}} \leqslant \hfill \\& \cdots {C^{n + 1}}{\left( {\frac{{{T^{\alpha - 1}}}}{{\varGamma \left( \alpha \right)}} + \frac{{{T^{\beta - 1}}}}{{\varGamma \left( \beta \right)}}} \right)^{n + 1}}\int_0^T \int_0^{{\xi _1}} \cdots \int_0^{{\xi _n}} {{{\left\| {{E_0}{\text{(}}{\xi _{n + 1}}{\text{)}}} \right\|}_\infty }} {\text{d}}{\xi _{n + 1}} \cdots {\text{d}}{\xi _1} \leqslant \hfill \\& {C^{n + 1}}{\left( {\frac{{{T^{\alpha - 1}}}}{{\varGamma \left( \alpha \right)}} + \frac{{{T^{\beta - 1}}}}{{\varGamma \left( \beta \right)}}} \right)^{n + 1}}\frac{{{T^{n + 1}}}}{{\left( {n + 1} \right){\text{!}}}}{\left\| {{E_0}{\text{(}}T{\text{)}}} \right\|_\infty } \hfill \\ \end{split} $ |
当
例 1 考虑如下时间分数阶logistic模型
$ {}_0^{\rm{C}}D_t^{{\text{1}}{\text{.5}}}u{\text{(}}t{\text{) = 0}}{\text{.2}}u\left( {1 - {\text{0}}{\text{.5}}u} \right) + f{\text{(}}t{\text{)}} $ | (13) |
式中:
取
$ \begin{split} {u_1}{\text{(}}t{\text{)}} = &\int_0^t {{J^{{\text{0}}{\text{.5}}}}( {\varGamma {\text{(}}2.5{\text{)}} - 0.{\text{2}}{\xi ^{1.5}} + 0.1{\xi ^3}} ){\text{d}}\tau } = \hfill \\& \int_0^t {\left( {1.5{\tau ^{0.5}} - \frac{{\varGamma {\text{(}}2.5{\text{)}}}}{{{\text{5}}\varGamma {\text{(}}3{\text{)}}}}{\tau ^2} + \frac{{\varGamma {\text{(4)}}}}{{10\varGamma {\text{(4}}{\text{.5)}}}}{\tau ^{3.5}}} \right){\text{d}}\tau } = \hfill \\& {t^{1.5}} - \frac{{\varGamma {\text{(}}2.5{\text{)}}}}{{{\text{15}}\varGamma {\text{(}}3{\text{)}}}}{t^3} + \frac{{\varGamma {\text{(4)}}}}{{45\varGamma {\text{(4}}{\text{.5)}}}}{t^{4.5}} \hfill \\ \end{split} $ |
表1列出了
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表 1 例1的数值误差结果 Table 1 Numerical error results for Example 1 |
例 2 考虑如下时间分数阶捕食者−食饵模型
$ {}_0^{\rm{C}}D_t^{{\text{1}}{\text{.4}}}u{\text{(}}t{\text{) = 0}}{\text{.2}}u\left( {1 - {\text{0}}{\text{.2}}u - {\text{0}}{\text{.1}}v} \right) + {g_1}{\text{(}}t{\text{)}} $ | (14) |
$ {}_0^{\rm{C}}D_t^{{\text{1}}{\text{.6}}}v{\text{(}}t{\text{) = 0}}{\text{.05}}v\left( { - 1 + {\text{0}}{\text{.02}}u - {\text{0}}{\text{.5}}v} \right) + {g_2}{\text{(}}t{\text{)}} $ | (15) |
式(14)~(15)中:
$ {g_1}{\text{(}}t{\text{)}} = \varGamma {\text{(}}2.{\text{4)}} - 0.2{t^{1.{\text{4}}}} + 0.04{t^{2.8}} + 0.02{t^3} $ |
$ {g_2}{\text{(}}t{\text{)}} = \varGamma {\text{(}}2.6{\text{)}} + 0.05{t^{1.6}} - 0.001{t^3} + 0.025{t^{3.2}} $ |
初值条件为
$\begin{split} {u}_{1}\text{(}t\text{)}= & {\displaystyle {\int }_{0}^{t}{J}^{\text{0}\text{.4}}(\varGamma \text{(}2.\text{4)}-0.2{\xi }^{1.\text{4}}+0.04{\xi }^{2.8}+0.02{\xi }^{3})\text{d}\tau }=\\& \displaystyle {\int }_{0}^{t}1.4{\tau }^{0.4}-\frac{\varGamma \text{(}2.4\text{)}}{\text{5}\varGamma \text{(}2.8\text{)}}{\tau }^{1.8} + \frac{\varGamma \text{(}3.8\text{)}}{\text{25}\varGamma \text{(}4.2\text{)}}{\tau }^{3.2} + \\& \frac{\varGamma \text{(4)}}{\text{5}0\varGamma \text{(4}\text{.4)}}{\tau }^{3.4}\text{d}\tau = {t}^{1.4}-\frac{\varGamma \text{(}2.4\text{)}}{\text{14}\varGamma \text{(}2.8\text{)}}{t}^{2.8}+ \\& \frac{\varGamma \text{(}3.8\text{)}}{\text{105}\varGamma \text{(}4.2\text{)}}{t}^{4.2}+\frac{\varGamma \text{(4)}}{220\varGamma \text{(4}\text{.4)}}{t}^{4.4} \end{split} $ |
$ \begin{split} {v_1}{\text{(}}t{\text{)}} = & \int_0^t {{J^{{\text{0}}{\text{.6}}}}( {\varGamma {\text{(}}2.6{\text{)}} + 0.05{\xi ^{1.6}} - 0.001{\xi ^3} + 0.025{\xi ^{3.2}}} ){\text{d}}\tau } = \hfill \\& \int_0^t 1.6{\tau ^{0.6}} + \frac{{\varGamma {\text{(}}2.6{\text{)}}}}{{20\varGamma {\text{(}}3.2{\text{)}}}}{\tau ^{2.2}} - \frac{{\varGamma {\text{(}}4{\text{)}}}}{{1\;000\varGamma {\text{(}}4.6{\text{)}}}}{\tau ^{3.6}} + \\& \frac{{\varGamma {\text{(4}}{\text{.2)}}}}{{40\varGamma {\text{(4}}{\text{.8)}}}}{\tau ^{3.8}}{\text{d}}\tau = \hfill {t^{1.6}} + \frac{{\varGamma {\text{(}}2.6{\text{)}}}}{{{\text{64}}\varGamma {\text{(}}3.2{\text{)}}}}{t^{3.2}} - \\& \frac{{\varGamma {\text{(}}4{\text{)}}}}{{4\;600\varGamma {\text{(}}4.6{\text{)}}}}{t^{4.6}} + \frac{{\varGamma {\text{(4}}{\text{.2)}}}}{{192\varGamma {\text{(4}}{\text{.8)}}}}{t^{4.8}} \hfill \\& \end{split}$ |
表2列出了
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表 2 例2的数值误差结果 Table 2 Numerical error results for Example 2 |
本文重点研究了一类分数阶捕食者−食饵模型。依据变分理论,对此类方程建立变分迭代格式,并严格地证明所建立格式的收敛性。最后,对2个模型进行数值模拟。模拟结果验证了该方法的可行性和有效性。
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